Chemistry
Chemistry
Problem
Between p-nitroaniline and p-methoxyaniline, which compound is the stronger base in aqueous solution? Give one sentence explaining how the para substituent affects electron density on the nitrogen.Intuitive explanation
The key is recognizing that basicity depends on how easily nitrogen can accept a proton—which requires electron density at the nitrogen atom. The methoxy group is an electron-donating group that pushes density toward the ring through resonance, while the nitro group withdraws electrons, making the nitrogen less nucleophilic. p-Methoxyaniline is the stronger base because its electron-donating substituent increases electron density on nitrogen, making it more available to bond with .
Intuitive explanation
The key is recognizing that basicity depends on how easily nitrogen can accept a proton—which requires electron density at the nitrogen atom. The methoxy group is an electron-donating group that pushes density toward the ring through resonance, while the nitro group withdraws electrons, making the nitrogen less nucleophilic. p-Methoxyaniline is the stronger base because its electron-donating substituent increases electron density on nitrogen, making it more available to bond with .