Mathematics

Mathematics

Problem

In right-angled triangle XYZXYZ with ∠Y=90∘\angle Y = 90^{\circ}, the lengths of the two sides adjacent to the right angle are XY=3k+2 cmXY = 3k + 2\,\text{cm} and YZ=4k−1 cmYZ = 4k - 1\,\text{cm}, where kk is a real number greater than 11. a. (i) Express the length of the hypotenuse XZXZ in terms of kk. b. (ii) For ∠X\angle X, obtain simplified expressions for sin⁡X\sin X and cos⁡X\cos X in terms of kk. c. (iii) Prove that sin⁡2X+cos⁡2X=1\sin^{2} X + \cos^{2} X = 1 for all permissible values of kk. d. (iv) If k=3k = 3, calculate the numerical values of tan⁡X\tan X and csc⁡X\csc X. (Leave answers as simplified fractions where possible.)
Intuitive explanation

The key is recognizing that the hypotenuse XZXZ must satisfy the Pythagorean theorem, and any constraint on the triangle (like a specific perimeter, area, or hypotenuse length) will give you an equation to solve for kk. Once you set up that equation using XZ2=(3k+2)2+(4k−1)2XZ^2 = (3k+2)^2 + (4k-1)^2, you'll have a quadratic in kk that determines the actual dimensions.

Intuitive explanation

The key is recognizing that the hypotenuse XZXZ must satisfy the Pythagorean theorem, and any constraint on the triangle (like a specific perimeter, area, or hypotenuse length) will give you an equation to solve for kk. Once you set up that equation using XZ2=(3k+2)2+(4k−1)2XZ^2 = (3k+2)^2 + (4k-1)^2, you'll have a quadratic in kk that determines the actual dimensions.

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