Classical Dynamics of Particles and Systems · Problem 3-36

Nonlinear Oscillations and Chaos — Marion & Thornton

Physics — Mechanics · greens-function-general-initial-conditions

Problem

Derive an expression for the displacement of a linear oscillator analogous to Equation 3.110 but for the initial conditions x(t0)=x0x(t_0) = x_0 and x˙(t0)=x˙0\dot{x}(t_0) = \dot{x}_0.
Intuitive explanation

The key is recognizing that any solution to the harmonic oscillator equation can be written as a linear combination of two independent solutions—you're just shifting the initial time from t=0t=0 to t=t0t=t_0 and adjusting the constants accordingly. Start by writing the general solution in terms of sin⁡\sin and cos⁡\cos functions (or complex exponentials), then apply your two initial conditions at t=t0t=t_0 to solve for the amplitude and phase (or the two coefficients). This gives you the displacement x(t)x(t) valid for all t≥t0t \geq t_0, expressed entirely in terms of x0x_0, x˙0\dot{x}_0, and the oscillator's natural frequency.

Intuitive explanation

The key is recognizing that any solution to the harmonic oscillator equation can be written as a linear combination of two independent solutions—you're just shifting the initial time from t=0t=0 to t=t0t=t_0 and adjusting the constants accordingly. Start by writing the general solution in terms of sin⁡\sin and cos⁡\cos functions (or complex exponentials), then apply your two initial conditions at t=t0t=t_0 to solve for the amplitude and phase (or the two coefficients). This gives you the displacement x(t)x(t) valid for all t≥t0t \geq t_0, expressed entirely in terms of x0x_0, x˙0\dot{x}_0, and the oscillator's natural frequency.

Related theory

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