Mathematics

Mathematics

Problem

Find the derivative of sec⁡−1(12x2−1)\sec^{-1}\left(\frac{1}{2x^2-1}\right) W.r.t. 1−x2\sqrt{1-x^2} at x=12x = \frac{1}{2}
Intuitive explanation

The key is recognizing that you're not finding dydx\frac{dy}{dx}, but rather dydu\frac{dy}{du} where u=1−x2u = \sqrt{1-x^2} is your new variable. Use the chain rule to connect the derivative of the inverse secant function to the rate of change of uu: dydu=dy/dxdu/dx\frac{dy}{du} = \frac{dy/dx}{du/dx}. Then substitute x=12x = \frac{1}{2} to evaluate at that specific point.

Intuitive explanation

The key is recognizing that you're not finding dydx\frac{dy}{dx}, but rather dydu\frac{dy}{du} where u=1−x2u = \sqrt{1-x^2} is your new variable. Use the chain rule to connect the derivative of the inverse secant function to the rate of change of uu: dydu=dy/dxdu/dx\frac{dy}{du} = \frac{dy/dx}{du/dx}. Then substitute x=12x = \frac{1}{2} to evaluate at that specific point.

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