Physics

Physics

Problem

During the powered ascent of a small test rocket, onboard instrumentation records that the engine’s power output increases linearly with time, from P0=1.0×102 WP_0 = 1.0\times10^{2}\,\text{W} at launch (t=0t=0) to Pf=7.0×102 WP_f = 7.0\times10^{2}\,\text{W} at t=4.0 st=4.0\,\text{s}. Throughout this interval the rocket’s mass remains effectively constant, and all engine power is converted into the rocket’s mechanical energy. (a) Derive an algebraic expression for the power P(t)P(t) as a function of time tt during the 4-s burn. (b) Determine the exact amount of work performed by the engine on the rocket during the burn, expressing your answer in joules. (c) Calculate the rocket’s average power output over the 4-s interval and verify that it matches an appropriate geometric interpretation of the power–time graph. (d) Discuss what the positive slope of P(t)P(t) implies about the engine’s operating conditions or fuel-combustion characteristics during the burn.
Intuitive explanation

The key insight is that power—the rate of energy delivery—is not constant here, so you can't use simple kinematic formulas. Instead, use the work-energy theorem: the total work done by the engine equals the change in kinetic energy plus the change in gravitational potential energy. Since power varies linearly with time, integrate P(t)P(t) to find total work, then solve for the final speed and height by accounting for gravity's competing effect.

Intuitive explanation

The key insight is that power—the rate of energy delivery—is not constant here, so you can't use simple kinematic formulas. Instead, use the work-energy theorem: the total work done by the engine equals the change in kinetic energy plus the change in gravitational potential energy. Since power varies linearly with time, integrate P(t)P(t) to find total work, then solve for the final speed and height by accounting for gravity's competing effect.

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