Physics

Physics

Problem

A solid brass sphere of mass 5.0 kg5.0\,\text{kg} is lowered into a mine shaft to a depth equal to 1%1\% of the Earth’s radius. a. (i) Calculate the value of gg at this depth, taking g=9.80 m s−2g = 9.80\,\text{m s}^{-2} at the surface and Earth’s radius R=6.4×106 mR = 6.4 \times 10^{6}\,\text{m}. b. (ii) Determine the weight of the sphere at this depth. c. (iii) Find the percentage decrease in weight compared with its weight at the surface.
Intuitive explanation

The key insight is that gravity decreases as you go deeper into the Earth, because only the mass below you contributes to the gravitational pull (by the shell theorem). This problem tests whether you can calculate the effective gravitational field inside a uniform sphere and compare it to surface gravity. You'll need to find what fraction of Earth's mass lies beneath the sphere, then use that to find the new weight—the mass of the brass itself barely changes, but the gravitational acceleration it experiences does.

Intuitive explanation

The key insight is that gravity decreases as you go deeper into the Earth, because only the mass below you contributes to the gravitational pull (by the shell theorem). This problem tests whether you can calculate the effective gravitational field inside a uniform sphere and compare it to surface gravity. You'll need to find what fraction of Earth's mass lies beneath the sphere, then use that to find the new weight—the mass of the brass itself barely changes, but the gravitational acceleration it experiences does.

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