Mathematics

Mathematics

Problem

Find the unit vector perpendicular to the plane r~⋅(2i~+j~+2k~)=5 \tilde{r} \cdot (2\tilde{i} + \tilde{j} + 2\tilde{k}) = 5 .
Intuitive explanation

The equation r~⋅(2i~+j~+2k~)=5\tilde{r} \cdot (2\tilde{i} + \tilde{j} + 2\tilde{k}) = 5 describes a plane, and the vector multiplying r~\tilde{r} is its normal vector—it points straight out of the plane. To find the unit normal, you just need to normalize this normal vector by dividing it by its own magnitude. This is a direct application of the plane equation's geometry.

Intuitive explanation

The equation r~⋅(2i~+j~+2k~)=5\tilde{r} \cdot (2\tilde{i} + \tilde{j} + 2\tilde{k}) = 5 describes a plane, and the vector multiplying r~\tilde{r} is its normal vector—it points straight out of the plane. To find the unit normal, you just need to normalize this normal vector by dividing it by its own magnitude. This is a direct application of the plane equation's geometry.

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