Problem

Problem

The figure shows velocity-time graph of a particle moving along a straight line. The velocity-time graph has a vertical axis 'v' in m/s, ranging from -20 to 10, and a horizontal axis 't' in seconds, with marks at 0, 1, 2, and 3. The graph is a straight line starting at (0, 10) and passing through (1, 0) and (2, -10). Identify the correct statement. a. The particle starts from the origin b. The particle crosses its initial position at t=2 st = 2 \text{ s} c. The average speed of the particle in the time interval, 0≤t≤2 s0 \le t \le 2 \text{ s} is zero d. All of the above
Intuitive explanation

This problem tests your understanding of how a velocity-time graph encodes motion: the slope tells you acceleration, while the area under the curve tells you displacement. Since the graph is a straight line, the acceleration is constant—you can read it directly from the slope. The key insight is recognizing that negative velocity doesn't mean the particle is slowing down; it means the particle has reversed direction. Use the slope to find aa, then think carefully about what negative vv represents physically.

Intuitive explanation

This problem tests your understanding of how a velocity-time graph encodes motion: the slope tells you acceleration, while the area under the curve tells you displacement. Since the graph is a straight line, the acceleration is constant—you can read it directly from the slope. The key insight is recognizing that negative velocity doesn't mean the particle is slowing down; it means the particle has reversed direction. Use the slope to find aa, then think carefully about what negative vv represents physically.

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