Chemistry

Chemistry

Problem

Calculate pH of basic solutions having [OH−][OH^-] as (a) [OH−]=0.05M[OH^-] = 0.05 M (b) [OH−]=5.0M[OH^-] = 5.0 M (c) [OH−]=10−8M[OH^-] = 10^{-8} M
Intuitive explanation

The key insight is that in basic solutions, [OH−][OH^-] tells you directly how many hydroxide ions are present—you just need to convert that to pHpH using the relationship between pOHpOH and pHpH. Start by finding pOHpOH from [OH−][OH^-] using the definition pOH=−log⁡[OH−]pOH = -\log[OH^-], then use the water equilibrium constant to find pH=14−pOHpH = 14 - pOH. This two-step process bridges the world of hydroxide concentration to the familiar pHpH scale.

Intuitive explanation

The key insight is that in basic solutions, [OH−][OH^-] tells you directly how many hydroxide ions are present—you just need to convert that to pHpH using the relationship between pOHpOH and pHpH. Start by finding pOHpOH from [OH−][OH^-] using the definition pOH=−log⁡[OH−]pOH = -\log[OH^-], then use the water equilibrium constant to find pH=14−pOHpH = 14 - pOH. This two-step process bridges the world of hydroxide concentration to the familiar pHpH scale.

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