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Mathematics
Mathematics
Problem
For
α
,
β
,
γ
∈
R
\alpha, \beta, \gamma \in \mathbf{R}
α
,
β
,
γ
∈
R
, if
lim
x
→
0
x
2
sin
α
x
+
(
γ
−
1
)
e
x
2
sin
2
x
−
β
x
=
3
\lim_{x \to 0} \frac{x^2 \sin \alpha x + (\gamma - 1)e^{x^2}}{\sin 2x - \beta x} = 3
lim
x
→
0
s
i
n
2
x
−
β
x
x
2
s
i
n
α
x
+
(
γ
−
1
)
e
x
2
=
3
, then
β
+
γ
−
α
\beta + \gamma - \alpha
β
+
γ
−
α
is equal to: (1) 7 (2) 4 (3) 6 (4) -1
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