Chemistry

Chemistry

Problem

A molecule A2BA_2B (molar mass = 166.4) occupies triclinic lattice with a=5 A˚a = 5 \text{ Å} , b=8 A˚b = 8 \text{ Å} and c=4 A˚c = 4 \text{ Å} . If density of A2BA_2B is 5.2 g cm−35.2 \text{ g cm}^{-3} , the number of molecules present in one unit cell is: a. 2 b. 3 c. 4 d. 5
Intuitive explanation

The key is connecting density, molar mass, and unit cell volume to find how many formula units fit inside. Use the density formula ρ=Z×MNA×Vcell\rho = \frac{Z \times M}{N_A \times V_{\text{cell}}}, where ZZ is the number of molecules per unit cell, MM is molar mass, NAN_A is Avogadro's number, and VcellV_{\text{cell}} is the unit cell volume in cm³. Calculate the volume from the lattice parameters, then rearrange to solve for ZZ—this tells you the stoichiometry of the crystal structure.

Intuitive explanation

The key is connecting density, molar mass, and unit cell volume to find how many formula units fit inside. Use the density formula ρ=Z×MNA×Vcell\rho = \frac{Z \times M}{N_A \times V_{\text{cell}}}, where ZZ is the number of molecules per unit cell, MM is molar mass, NAN_A is Avogadro's number, and VcellV_{\text{cell}} is the unit cell volume in cm³. Calculate the volume from the lattice parameters, then rearrange to solve for ZZ—this tells you the stoichiometry of the crystal structure.

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