Mathematics

Mathematics

Problem

State the necessary conditions on dxdt\dfrac{dx}{dt} and dydt\dfrac{dy}{dt} for a parametric curve x=f(t), y=g(t)x=f(t),\,y=g(t) to have a vertical tangent at the point corresponding to t=t0t=t_0.
Intuitive explanation

A vertical tangent means the slope is undefined—which happens when the denominator of dydx\frac{dy}{dx} blows up. Since dydx=dy/dtdx/dt\frac{dy}{dx} = \frac{dy/dt}{dx/dt}, you need the denominator to be zero while the numerator stays nonzero. So the key condition is dxdt=0\frac{dx}{dt} = 0 at t=t0t = t_0, but dydt≠0\frac{dy}{dt} \neq 0 at that same point—this ensures the curve is actually moving vertically, not just stalling out.

Intuitive explanation

A vertical tangent means the slope is undefined—which happens when the denominator of dydx\frac{dy}{dx} blows up. Since dydx=dy/dtdx/dt\frac{dy}{dx} = \frac{dy/dt}{dx/dt}, you need the denominator to be zero while the numerator stays nonzero. So the key condition is dxdt=0\frac{dx}{dt} = 0 at t=t0t = t_0, but dydt≠0\frac{dy}{dt} \neq 0 at that same point—this ensures the curve is actually moving vertically, not just stalling out.

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