Physics

Physics

Problem

A particle moves along the xx-axis under a potential energy V(x)=ax2V(x)=a x^{2}, where a>0a>0 is a constant. Which statement about the point x=0x=0 is correct? a) Force is non-zero at x=0x=0 and directed toward the origin. b) Force is zero at x=0x=0 and the equilibrium is stable. c) Force is zero at x=0x=0 and the equilibrium is unstable. d) Force is zero at x=0x=0 and the equilibrium is neutral.
Intuitive explanation

The key here is recognizing that x=0x=0 is an equilibrium point, and you need to determine its stability by examining the force and potential energy curve. Since V(x)=ax2V(x) = ax^2 is a parabola opening upward with its minimum at the origin, the force F=−dVdxF = -\frac{dV}{dx} points back toward x=0x=0 from either side—making it a stable equilibrium. Think of it like a ball at the bottom of a bowl: any small displacement creates a restoring force that pulls the particle back.

Intuitive explanation

The key here is recognizing that x=0x=0 is an equilibrium point, and you need to determine its stability by examining the force and potential energy curve. Since V(x)=ax2V(x) = ax^2 is a parabola opening upward with its minimum at the origin, the force F=−dVdxF = -\frac{dV}{dx} points back toward x=0x=0 from either side—making it a stable equilibrium. Think of it like a ball at the bottom of a bowl: any small displacement creates a restoring force that pulls the particle back.

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