Mathematics

Mathematics

Problem

Define the function pp by p(x)={x2−9x−3,x<3,6,x=3,x−3+6,x>3.p(x)=\begin{cases} \dfrac{x^{2}-9}{x-3}, & x<3,\\ 6, & x=3,\\ \sqrt{x-3}+6, & x>3. \end{cases} Determine the domain of p′(x)p'(x) and express your answer in interval notation.
Intuitive explanation

The key is recognizing that p′(x)p'(x) exists only where pp is differentiable, which requires continuity and a well-defined derivative from both sides. First, simplify the left piece—it factors nicely and isn't actually the discontinuous mess it appears. Then check if pp is continuous at x=3x=3 by comparing the limit from each side with p(3)p(3). Finally, compute one-sided derivatives at x=3x=3 to see if they match; if they don't, that point is excluded from the domain of p′p'.

Intuitive explanation

The key is recognizing that p′(x)p'(x) exists only where pp is differentiable, which requires continuity and a well-defined derivative from both sides. First, simplify the left piece—it factors nicely and isn't actually the discontinuous mess it appears. Then check if pp is continuous at x=3x=3 by comparing the limit from each side with p(3)p(3). Finally, compute one-sided derivatives at x=3x=3 to see if they match; if they don't, that point is excluded from the domain of p′p'.

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