Earth's rotation speed at equator · CAP 2006 #2

Physics · mechanics

Problem

The radius of the Earth is 6.37·10⁶m. Approximately how fast is a person on the Equator moving due to the Earth rotation? (a) 5 m/s (b) 50 m/s (c) 500 m/s (d) 5000 m/s
Intuitive explanation

A person on the Equator travels in a circle once per day, so you need to find the circumference of Earth and divide by the time for one rotation. The key insight is that v=2πrTv = \frac{2\pi r}{T}, where rr is Earth's radius and TT is one day in seconds—this converts rotational motion into linear speed. Plug in the numbers carefully, paying attention to unit conversions between meters and seconds.

Intuitive explanation

A person on the Equator travels in a circle once per day, so you need to find the circumference of Earth and divide by the time for one rotation. The key insight is that v=2πrTv = \frac{2\pi r}{T}, where rr is Earth's radius and TT is one day in seconds—this converts rotational motion into linear speed. Plug in the numbers carefully, paying attention to unit conversions between meters and seconds.

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