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Physics
Physics
Problem
A 'seconds pendulum' is defined as a pendulum with a time period of exactly
2.0
s
2.0\,\text{s}
2.0
s
. Calculate the required effective length of such a pendulum on a planet where the acceleration due to gravity is
g
=
10
m/s
2
g = 10\,\text{m/s}^{2}
g
=
10
m/s
2
. (Take
π
2
≈
10
\pi^{2} \approx 10
π
2
≈
10
for calculation).
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