Mathematics

Mathematics

Problem

The coordinates of a point on a circle of radius aa are given by x=acos⁡t,  y=asin⁡tx = a\cos t,\; y = a\sin t. Determine d2ydx2\dfrac{d^{2}y}{dx^{2}} in terms of tt and hence find its value when t=π2t = \dfrac{\pi}{2}.
Intuitive explanation

You're working with a parametric curve, so the key is to use the chain rule twice—first to find dydx\frac{dy}{dx} by dividing derivatives with respect to tt, then to find the second derivative by differentiating that ratio again with respect to xx. The second derivative tells you how the slope itself is changing, which relates to the curvature of the circle. Once you have the general formula, substituting t=π2t = \frac{\pi}{2} pinpoints the curvature at the top of the circle.

Intuitive explanation

You're working with a parametric curve, so the key is to use the chain rule twice—first to find dydx\frac{dy}{dx} by dividing derivatives with respect to tt, then to find the second derivative by differentiating that ratio again with respect to xx. The second derivative tells you how the slope itself is changing, which relates to the curvature of the circle. Once you have the general formula, substituting t=π2t = \frac{\pi}{2} pinpoints the curvature at the top of the circle.

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