Physics

Physics · optics

Problem

(1) Find the amplitude, frequency, wavelength, and speed of propagation of the wave described by the equation y=0.2cos⁡[π(5t−2x)]y=0.2 \cos [\pi(5 t-2 x)] Here, the units of length and time are taken to be meter and second, respectively. (2) When a sinusoidal wave of amplitude 0.1 m and frequency 2 Hz travels at a speed of 2 m/s2 \mathrm{~m} / \mathrm{s} in the −x-x direction, derive the expression for the displacement yy at position xx at time tt by using an integer, nn. Here, we assume that the displacement at the origin (x=0)(x=0) at time t=0t=0 is zero, i.e., y=0y=0.
Intuitive explanation
PART (1)
Wave equations encode all their properties in their coefficients—you just need to match the standard form y=Acos⁡(kx−ωt)y = A\cos(kx - \omega t) (or its rearrangement) to read off amplitude, angular frequency, and wavenumber, then use the relationships v=ω/kv = \omega/k and λ=2π/k\lambda = 2\pi/k to find the remaining quantities.
PART (2)
A wave traveling in the −x-x direction has the form y=Asin⁡(ωt+kx+ϕ)y = A\sin(\omega t + kx + \phi) or cos⁡\cos with an appropriate phase. The key is using the boundary condition y(0,0)=0y(0,0) = 0 to pin down the phase constant, then expressing wavelength in terms of the given speed and frequency.
Intuitive explanation
PART (1)
Wave equations encode all their properties in their coefficients—you just need to match the standard form y=Acos⁡(kx−ωt)y = A\cos(kx - \omega t) (or its rearrangement) to read off amplitude, angular frequency, and wavenumber, then use the relationships v=ω/kv = \omega/k and λ=2π/k\lambda = 2\pi/k to find the remaining quantities.
PART (2)
A wave traveling in the −x-x direction has the form y=Asin⁡(ωt+kx+ϕ)y = A\sin(\omega t + kx + \phi) or cos⁡\cos with an appropriate phase. The key is using the boundary condition y(0,0)=0y(0,0) = 0 to pin down the phase constant, then expressing wavelength in terms of the given speed and frequency.

Related theory

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