Mathematics

Mathematics

Problem

Prove that tan⁡α+2tan⁡2α+4tan⁡4α+8cot⁡8α=cot⁡α\tan \alpha + 2 \tan 2\alpha + 4 \tan 4\alpha + 8 \cot 8\alpha = \cot \alpha
Intuitive explanation

The key is to recognize that this sum has a telescoping structure hidden in the tangent and cotangent identities. Notice the doubling pattern in the angles (α,2α,4α,8α\alpha, 2\alpha, 4\alpha, 8\alpha) and coefficients (1,2,4,81, 2, 4, 8)—this suggests using the identity cot⁡θ−tan⁡θ=2cot⁡2θ\cot \theta - \tan \theta = 2\cot 2\theta repeatedly to collapse the left side. Work backwards from cot⁡α\cot \alpha by expressing it in terms of larger angles, and you'll see how each term cancels strategically.

Intuitive explanation

The key is to recognize that this sum has a telescoping structure hidden in the tangent and cotangent identities. Notice the doubling pattern in the angles (α,2α,4α,8α\alpha, 2\alpha, 4\alpha, 8\alpha) and coefficients (1,2,4,81, 2, 4, 8)—this suggests using the identity cot⁡θ−tan⁡θ=2cot⁡2θ\cot \theta - \tan \theta = 2\cot 2\theta repeatedly to collapse the left side. Work backwards from cot⁡α\cot \alpha by expressing it in terms of larger angles, and you'll see how each term cancels strategically.

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