Find ∫tan⁡(ln⁡x) sec⁡2(ln⁡x)x dx\displaystyle\int \frac{\tan(\ln x)\,\sec^{2}(\ln x)}{x}\,dx.

Mathematics

Problem

Find ∫tan⁡(ln⁡x) sec⁡2(ln⁡x)x dx\displaystyle\int \frac{\tan(\ln x)\,\sec^{2}(\ln x)}{x}\,dx.
Intuitive explanation

The key is recognizing that ln⁡x\ln x is "hiding" inside the trig functions—a classic setup for uu-substitution. Notice that the derivative of ln⁡x\ln x is 1x\frac{1}{x}, which appears in the denominator, and sec⁡2(ln⁡x)\sec^2(\ln x) is the derivative of tan⁡(ln⁡x)\tan(\ln x). This means you have a composition where the inner function's derivative is already present, letting you collapse the integral into a simple power form.

Intuitive explanation

The key is recognizing that ln⁡x\ln x is "hiding" inside the trig functions—a classic setup for uu-substitution. Notice that the derivative of ln⁡x\ln x is 1x\frac{1}{x}, which appears in the denominator, and sec⁡2(ln⁡x)\sec^2(\ln x) is the derivative of tan⁡(ln⁡x)\tan(\ln x). This means you have a composition where the inner function's derivative is already present, letting you collapse the integral into a simple power form.

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