Physics

Physics

Problem

The displacement xx (in metres) of a particle moving along a straight line varies with time tt (in seconds) as described below: • For 0≤t≤5 s0 \leq t \leq 5\,\text{s}, displacement increases uniformly from 0 m0\,\text{m} to 10 m10\,\text{m}. • For 5 s<t≤10 s5\,\text{s} < t \leq 10\,\text{s}, displacement increases from 10 m10\,\text{m} to 40 m40\,\text{m} with constant acceleration. • For 10 s<t≤13 s10\,\text{s} < t \leq 13\,\text{s}, displacement remains constant at 40 m40\,\text{m}. Answer the following: a. (i) Draw the position–time (xx–tt) graph representing the motion for the interval 0≤t≤13 s0 \leq t \leq 13\,\text{s}. b. (ii) From the graph, determine the instantaneous velocity of the particle at t=5 st = 5\,\text{s}. c. (iii) Determine the magnitude of the constant acceleration during the interval 5 s<t≤10 s5\,\text{s} < t \leq 10\,\text{s}. d. (iv) Draw the corresponding velocity–time (vv–tt) graph for the complete 13 s13\,\text{s} of motion.
Intuitive explanation

This problem asks you to extract motion information from a piecewise displacement description—the key is recognizing that each segment has a different kinematic character. In the first phase, uniform increase means constant velocity; in the second, you'll need to find the acceleration from the change in displacement and time; in the third, no change means zero velocity. Sketch or write out the xx–tt relationship for each interval, then use slopes and curvature to find velocity and acceleration in each region.

Intuitive explanation

This problem asks you to extract motion information from a piecewise displacement description—the key is recognizing that each segment has a different kinematic character. In the first phase, uniform increase means constant velocity; in the second, you'll need to find the acceleration from the change in displacement and time; in the third, no change means zero velocity. Sketch or write out the xx–tt relationship for each interval, then use slopes and curvature to find velocity and acceleration in each region.

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