Mathematics

Mathematics

Problem

Let g(x)=sin⁡4x  ln⁡xx2g(x)=\dfrac{\sin 4x\;\ln x}{x^{2}}. Simplify g′(x)g'(x). a) 4xln⁡xcos⁡4x−2sin⁡4xln⁡xx3\dfrac{4x\ln x\cos4x-2\sin4x\ln x}{x^{3}} b) 4x2ln⁡xcos⁡4x+sin⁡4x−2sin⁡4xln⁡xx4\dfrac{4x^{2}\ln x\cos4x+\sin4x-2\sin4x\ln x}{x^{4}} c) 4xln⁡xcos⁡4x+sin⁡4x−2sin⁡4xln⁡xx3\dfrac{4x\ln x\cos4x+\sin4x-2\sin4x\ln x}{x^{3}} d) xln⁡xcos⁡4x+sin⁡4x−2sin⁡4xln⁡xx3\dfrac{x\ln x\cos4x+\sin4x-2\sin4x\ln x}{x^{3}}

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