Physics

Physics

Problem

A wire of resistance 15 Ω15\,\Omega carries a current of 2.0 A2.0\,\text{A} for 5 s5\,\text{s}. How much electrical energy is converted into heat in this time? a) 60 J60\,\text{J} b) 600 J600\,\text{J} c) 300 J300\,\text{J} d) 150 J150\,\text{J}
Intuitive explanation

This problem is about Joule heating—the conversion of electrical energy into thermal energy as current flows through a resistive material. The key insight is that power dissipated in a resistor is P=I2RP = I^2R, and multiplying that power by the time interval gives you the total energy converted. Think of it as: the more current, the more collisions between electrons and atoms; the more resistance, the harder those collisions; and the longer it runs, the more total heat accumulates.

Intuitive explanation

This problem is about Joule heating—the conversion of electrical energy into thermal energy as current flows through a resistive material. The key insight is that power dissipated in a resistor is P=I2RP = I^2R, and multiplying that power by the time interval gives you the total energy converted. Think of it as: the more current, the more collisions between electrons and atoms; the more resistance, the harder those collisions; and the longer it runs, the more total heat accumulates.

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