Physics

Physics

Problem

A horizontal force of 12 N12\,\text{N} is just sufficient to start a 2.0 kg2.0\,\text{kg} wooden block moving on a horizontal table. Calculate the coefficient of static friction between the block and the table.
Intuitive explanation

The key insight is recognizing that "just sufficient to start moving" means you're at the threshold where applied force equals maximum static friction. Static friction isn't a fixed value—it grows with the normal force until it hits its limit, fs,max⁡=μsNf_{s,\max} = \mu_s N. Since the block is on a horizontal table, the normal force equals the weight, so you can set the applied force equal to μsmg\mu_s mg and solve for μs\mu_s.

Intuitive explanation

The key insight is recognizing that "just sufficient to start moving" means you're at the threshold where applied force equals maximum static friction. Static friction isn't a fixed value—it grows with the normal force until it hits its limit, fs,max⁡=μsNf_{s,\max} = \mu_s N. Since the block is on a horizontal table, the normal force equals the weight, so you can set the applied force equal to μsmg\mu_s mg and solve for μs\mu_s.

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