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Mathematics
Mathematics
Problem
If
y
=
a
log
x
+
b
x
2
+
x
y = a \log x + bx^2 + x
y
=
a
lo
g
x
+
b
x
2
+
x
has its extremum value at
x
=
1
x = 1
x
=
1
and
x
=
2
x = 2
x
=
2
, then
(
a
,
b
)
=
(a, b) =
(
a
,
b
)
=
(a)
(
1
,
1
2
)
\left(1, \frac{1}{2}\right)
(
1
,
2
1
)
(b)
(
1
2
,
2
)
\left(\frac{1}{2}, 2\right)
(
2
1
,
2
)
(c)
(
2
,
−
1
2
)
\left(2, \frac{-1}{2}\right)
(
2
,
2
−
1
)
(d)
(
−
2
3
,
−
1
6
)
\left(\frac{-2}{3}, \frac{-1}{6}\right)
(
3
−
2
,
6
−
1
)
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