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Mathematics
Mathematics
Problem
Compute
∫
0
2
2
1
+
(
3
−
2
x
)
2
d
x
\displaystyle\int_{0}^{2}\frac{2}{1+(3-2x)^{2}}\,dx
∫
0
2
1
+
(
3
−
2
x
)
2
2
d
x
. a)
arctan
3
\arctan 3
arctan
3
b)
2
arctan
3
2\arctan 3
2
arctan
3
c)
arctan
3
+
π
4
\arctan 3 + \dfrac{\pi}{4}
arctan
3
+
4
π
d)
arctan
3
−
π
4
\arctan 3 - \dfrac{\pi}{4}
arctan
3
−
4
π
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