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Mathematics
Mathematics
Problem
If
A
=
π
5
A = \frac{\pi}{5}
A
=
5
π
, then find the value of
∑
r
=
1
8
tan
(
r
A
)
⋅
tan
(
(
r
+
1
)
A
)
.
\sum_{r=1}^{8} \tan(rA) \cdot \tan((r+1)A).
r
=
1
∑
8
tan
(
r
A
)
⋅
tan
((
r
+
1
)
A
)
.
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