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A Modern Approach to Quantum Mechanics · Problem 5.3
Wave Mechanics in One Dimension — John S. Townsend
Physics — Quantum Mechanics · singlet-state-arbitrary-direction-basis
Problem Express the total-spin s = 0 s = 0 s = 0 state of two spin-1 2 \frac{1}{2} 2 1 particles given in (5.31) in terms of the states ∣ + n , − n ⟩ |{+\mathbf{n}}, {-\mathbf{n}}\rangle ∣ + n , − n ⟩ and ∣ − n , + n ⟩ |{-\mathbf{n}}, {+\mathbf{n}}\rangle ∣ − n , + n ⟩ , where for a single spin-1 2 \frac{1}{2} 2 1 particle
∣ + n ⟩ = cos θ 2 ∣ + z ⟩ + e i ϕ sin θ 2 ∣ − z ⟩ ∣ − n ⟩ = sin θ 2 ∣ + z ⟩ − e i ϕ cos θ 2 ∣ − z ⟩ \begin{aligned}
|{+\mathbf{n}}\rangle &= \cos\frac{\theta}{2}|{+z}\rangle + e^{i\phi}\sin\frac{\theta}{2}|{-z}\rangle \\
|{-\mathbf{n}}\rangle &= \sin\frac{\theta}{2}|{+z}\rangle - e^{i\phi}\cos\frac{\theta}{2}|{-z}\rangle
\end{aligned} ∣ + n ⟩ ∣ − n ⟩ = cos 2 θ ∣ + z ⟩ + e i ϕ sin 2 θ ∣ − z ⟩ = sin 2 θ ∣ + z ⟩ − e i ϕ cos 2 θ ∣ − z ⟩
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