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Mathematics
Mathematics
Problem
Determine the value of
a
a
a
that makes the function continuous at
x
=
3
x=3
x
=
3
.
g
(
x
)
=
{
x
2
−
9
x
−
3
,
x
≠
3
,
a
,
x
=
3.
g(x)= \begin{cases} \dfrac{x^{2}-9}{x-3}, & x\neq 3,\\ a, & x=3. \end{cases}
g
(
x
)
=
⎩
⎨
⎧
x
−
3
x
2
−
9
,
a
,
x
=
3
,
x
=
3.
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