Problem

Problem

A particle is released from a certain height H=400 mH = 400 \text{ m} . Due to the wind, the particle gathers the horizontal velocity component vx=ayv_x = ay where a=5 s−1a = \sqrt{5} \text{ s}^{-1} and yy is the vertical displacement of the particle from the point of release, then find (Take g=10 m/s2g = 10 \text{ m/s}^2 ) a. the horizontal drift of the particle when it strikes the ground, b. the speed with which particle strikes the ground.

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