Chemistry

Chemistry

Problem

For a reaction the Rate Law is Rate=k[A]a[C]b\text{Rate} = k[A]^a[C]^b Where 'C' act as catalyst. At an initial concentration [A]=0.1 M[A] = 0.1 \text{ M}, [C]=0.01 M[C] = 0.01 \text{ M}, t1/3t_{1/3} and t5/9t_{5/9} was found to be 30 min and 75 min respectively. But t1/3t_{1/3} was found to be 7.5 min if initial concentration are [A]=0.2 M[A] = 0.2 \text{ M} and [C]=0.02 M[C] = 0.02 \text{ M}. Select the correct option(s). [Given txt_x is time required for x fraction of reactant the react] (A) a=2a = 2 (B) b=2b = 2 (C) When initial concentration are [A]=0.2 M[A] = 0.2 \text{ M}, [C]=0.02 M[C] = 0.02 \text{ M}, t5/9t_{5/9} is 18.75 min. (D) When initial concentration are [A]=0.2 M[A] = 0.2 \text{ M}, [C]=0.02 M[C] = 0.02 \text{ M}, t5/9t_{5/9} is 22.5 min.

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