Mathematics

Problem

A pendulum of length

2\text{ m}

swings so that the angle

\theta

it makes with the vertical is decreasing at

0.40\text{ rad/s}

when

\theta=\pi/6

. At that instant, what is the rate of change of the bob’s height

h

above its lowest point,

dh/dt

, in m/s? a)

0.40\text{ m/s}

-0.20\text{ m/s}

-0.40\text{ m/s}

-0.69\text{ m/s}