Mathematics

Mathematics

Problem

∫[f(x)g′′(x)−f′′(x)g(x)] dx\int [f(x)g''(x) - f''(x)g(x)]\,dx (a) f(x)g′(x)\frac{f(x)}{g'(x)} (b) f′(x)g(x)−f(x)g′(x)f'(x)g(x) - f(x)g'(x) (c) f(x)g′(x)−f′(x)g(x)f(x)g'(x) - f'(x)g(x) (d) f(x)g′(x)+f′(x)g(x)f(x)g'(x) + f'(x)g(x) (a) f(x)g′(x)\frac{f(x)}{g'(x)} (b) f′(x)g(x)−f(x)g′(x)f'(x)g(x) - f(x)g'(x) (c) f(x)g′(x)−f′(x)g(x)f(x)g'(x) - f'(x)g(x) (d) f(x)g′(x)+f′(x)g(x)f(x)g'(x) + f'(x)g(x)

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