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Chemistry
Chemistry
Problem
At 40 °C the ionic product of water is
2.92
×
10
−
14
2.92 \times 10^{-14}
2.92
×
1
0
−
14
. Piperidine (C
5
_5
5
H
11
_{11}
11
N) has
K
b
=
4.3
×
10
−
3
K_b = 4.3 \times 10^{-3}
K
b
=
4.3
×
1
0
−
3
. Calculate the pH of a 0.50 M aqueous piperidine solution at 40 °C.
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