Chemistry

Chemistry

Problem

At 40 ∘C40\,^{\circ}\mathrm{C}, the ion-product constant of water is Kw=2.92×10−14K_w = 2.92\times10^{-14}. A 0.20 M0.20\,\text{M} solution of the weak base BOH\mathrm{BOH} has Kb=2.2×10−5K_b = 2.2\times10^{-5}. What is the pH of the solution at 40 ∘C40\,^{\circ}\mathrm{C}? a) 11.52 b) 10.86 c) 11.32 d) 10.46

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