Mathematics

Mathematics

Problem

Determine ∫ln⁡(5x−1) dx\displaystyle\int \ln(5x-1)\,dx. a) (5x−1)ln⁡(5x−1)−(5x−1)+C (5x-1)\ln(5x-1) - (5x-1) + C b) (5x−1)ln⁡(5x−1)−(5x−1)5+C\dfrac{(5x-1)\ln(5x-1) - (5x-1)}{5} + C c) x ln⁡(5x−1)−x+Cx\,\ln(5x-1) - x + C d) ln⁡2(5x−1)10+C\dfrac{\ln^{2}(5x-1)}{10} + C

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