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Mathematics
Problem
The area (in square units) bounded by the curves
y
=
x
y = \sqrt{x}
y
=
x
,
2
y
−
x
+
3
=
0
2y - x + 3 = 0
2
y
−
x
+
3
=
0
, x-axis and lying in the first quadrant is : [JEE (Main)-2013] (1) 9 (2) 36 (3) 18 (4)
27
4
\frac{27}{4}
4
27
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