Determine whether the series n=1∑∞(n3+4)4/3n2 converges or diverges.
a) The series diverges because, for large n, its terms behave like 1/n1/3, and p<1.
b) The series converges because, for large n, its terms behave like 1/n2, a p-series with p>1.
c) The series diverges for the same reason that the harmonic series ∑1/n diverges.
d) The series fails the nth-term test for convergence since n→∞lim(n3+4)4/3n2=0."