Mathematics

Mathematics

Problem

The temperature T(t)T(t) (in kelvins) of a chemical reactor satisfies dTdt=tetT,T>0,\frac{dT}{dt}=\frac{t e^{t}}{T},\qquad T>0, where tt is measured in hours. a. Find the general solution of the differential equation, expressing your answer in explicit form T=f(t)T=f(t). b. At t=0t=0, the temperature is measured to be 300 K300\,\text{K}. Determine the explicit particular solution that satisfies this initial condition. c. Using your solution from part (b), compute d2Tdt2\displaystyle\frac{d^{2}T}{dt^{2}} at t=0t=0 and interpret its sign in terms of whether the temperature is initially accelerating upward or downward.

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