Physics

Physics

Problem

For upward motion under resistance, the time of ascent is Ta=ug+F/mT_a = \frac{u}{g + F/m}; for downward motion through the same height HH, the time of descent is Td=2Hg−F/mT_d = \sqrt{\frac{2H}{g - F/m}}. Based on these expressions only, determine the correct comparison between TdT_d and TaT_a by selecting one of the following inside your explanation: (A) Td>TaT_d > T_a, (B) Td<TaT_d < T_a, (C) Td=TaT_d = T_a, (D) cannot be concluded.

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