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Mathematics
Problem
A hyperbola is centred at the origin, has vertices at
(
±
4
,
0
)
(\pm4,0)
(
±
4
,
0
)
and its asymptotes are
y
=
±
3
4
x
y=\pm\dfrac{3}{4}x
y
=
±
4
3
x
. Which of the following is its equation? a)
y
2
16
−
x
2
9
=
1
\dfrac{y^{2}}{16}-\dfrac{x^{2}}{9}=1
16
y
2
−
9
x
2
=
1
b)
x
2
16
+
y
2
9
=
1
\dfrac{x^{2}}{16}+\dfrac{y^{2}}{9}=1
16
x
2
+
9
y
2
=
1
c)
x
2
16
−
y
2
9
=
1
\dfrac{x^{2}}{16}-\dfrac{y^{2}}{9}=1
16
x
2
−
9
y
2
=
1
d)
x
2
9
−
y
2
16
=
1
\dfrac{x^{2}}{9}-\dfrac{y^{2}}{16}=1
9
x
2
−
16
y
2
=
1
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