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Problem
Problem
In parallel grouping (Case 2) prove that,
E
e
q
=
E
E_{eq} = E
E
e
q
=
E
if
E
1
=
E
2
=
⋯
=
E
E_1 = E_2 = \dots = E
E
1
=
E
2
=
⋯
=
E
and
r
1
=
r
2
=
⋯
=
r
r_1 = r_2 = \dots = r
r
1
=
r
2
=
⋯
=
r
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