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Mathematics
Mathematics
Problem
Prove that:
sin
20
∘
sin
40
∘
sin
80
∘
=
3
8
\sin 20^{\circ} \sin 40^{\circ} \sin 80^{\circ}=\frac{\sqrt{3}}{8}
sin
2
0
∘
sin
4
0
∘
sin
8
0
∘
=
8
3
.
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