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Physics
Physics
Problem
A cup of tea cools from
80
∘
C
80^\circ\text{C}
8
0
∘
C
to
60
∘
C
60^\circ\text{C}
6
0
∘
C
in one minute. The ambient temperature is
30
∘
C
30^\circ\text{C}
3
0
∘
C
. In cooling from
60
∘
C
60^\circ\text{C}
6
0
∘
C
to
50
∘
C
50^\circ\text{C}
5
0
∘
C
. It will take : (A) 50 s (B) 90 s (C) 60 s (D) 48 s (A) 50 s (B) 90 s (C) 60 s (D) 48 s
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