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Chemistry
Chemistry
Problem
The emf of the cell,
N
i
∣
N
i
2
+
(
1.0
M
)
∣
∣
A
g
+
(
1.0
M
)
∣
A
g
Ni | Ni^{2+} (1.0 \text{ M}) || Ag^+ (1.0 \text{ M}) | Ag
N
i
∣
N
i
2
+
(
1.0
M
)
∣∣
A
g
+
(
1.0
M
)
∣
A
g
[
E
∘
E^\circ
E
∘
for
N
i
2
+
/
N
i
=
−
0.25
Ni^{2+} / Ni = -0.25
N
i
2
+
/
N
i
=
−
0.25
volt,
E
∘
E^\circ
E
∘
for
A
g
+
/
A
g
=
0.80
Ag^+ / Ag = 0.80
A
g
+
/
A
g
=
0.80
volt] is given by : (a)
−
0.25
+
0.80
=
0.55
-0.25 + 0.80 = 0.55
−
0.25
+
0.80
=
0.55
volt (b)
−
0.25
−
(
+
0.80
)
=
−
1.05
-0.25 - (+0.80) = -1.05
−
0.25
−
(
+
0.80
)
=
−
1.05
volt (c)
+
0.80
−
(
−
0.25
)
=
+
1.05
+0.80 - (-0.25) = +1.05
+
0.80
−
(
−
0.25
)
=
+
1.05
volt (d)
−
0.80
−
(
−
0.25
)
=
−
0.55
-0.80 - (-0.25) = -0.55
−
0.80
−
(
−
0.25
)
=
−
0.55
volt
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