Mathematics

Mathematics

Problem

A solution curve to dydx=2y−3x+4\dfrac{dy}{dx}=\dfrac{2y-3}{x+4} passes through (−2,2)(-2,2). Which equation represents this curve? a) y=14(x+4)2+32y=\dfrac{1}{4}(x+4)^{2}+\dfrac{3}{2} b) y=18(x+4)2−32y=\dfrac{1}{8}(x+4)^{2}-\dfrac{3}{2} c) y=−18(x+4)2+32y=-\dfrac{1}{8}(x+4)^{2}+\dfrac{3}{2} d) y=18(x+4)2+32y=\dfrac{1}{8}(x+4)^{2}+\dfrac{3}{2}

Browse the problem library