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Physics
Physics
Problem
A planet has the same mass as Earth but twice Earth’s radius. If
v
E
v_E
v
E
is the escape speed from Earth’s surface, what is the escape speed
v
P
v_P
v
P
from the planet’s surface? a)
v
P
=
v
E
2
v_P = \dfrac{v_E}{2}
v
P
=
2
v
E
b)
v
P
=
v
E
2
v_P = \dfrac{v_E}{\sqrt{2}}
v
P
=
2
v
E
c)
v
P
=
v
E
v_P = v_E
v
P
=
v
E
d)
v
P
=
2
v
E
v_P = \sqrt{2}\,v_E
v
P
=
2
v
E
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