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Problem Given h ( x ) = ( x 2 + 1 ) sec x cot x h(x)=(x^{2}+1)\sec x\cot x h ( x ) = ( x 2 + 1 ) sec x cot x h ′ ( x ) h'(x) h ′ ( x ) sec x [ 2 x cot x + ( x 2 + 1 ) ] \sec x\left[2x\cot x+(x^{2}+1)\right] sec x [ 2 x cot x + ( x 2 + 1 ) ] sec x [ 2 x cot x + ( x 2 + 1 ) − ( x 2 + 1 ) csc 2 x ] \sec x\left[2x\cot x+(x^{2}+1)-(x^{2}+1)\csc^{2}x\right] sec x [ 2 x cot x + ( x 2 + 1 ) − ( x 2 + 1 ) csc 2 x ] sec x [ 2 x cot x + ( x 2 + 1 ) tan x − ( x 2 + 1 ) csc 2 x ] \sec x\left[2x\cot x+(x^{2}+1)\tan x-(x^{2}+1)\csc^{2}x\right] sec x [ 2 x cot x + ( x 2 + 1 ) tan x − ( x 2 + 1 ) csc 2 x ] sec x [ 2 x cot x + ( x 2 + 1 ) + ( x 2 + 1 ) csc 2 x ] \sec x\left[2x\cot x+(x^{2}+1)+(x^{2}+1)\csc^{2}x\right] sec x [ 2 x cot x + ( x 2 + 1 ) + ( x 2 + 1 ) csc 2 x ] Browse the problem library