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Problem
Problem
The locus of the mid-point of that chord of parabola which subtends right angle on the vertex will be a.
y
2
−
2
a
x
+
8
a
2
=
0
y^2 - 2ax + 8a^2 = 0
y
2
−
2
a
x
+
8
a
2
=
0
b.
y
2
=
a
(
x
−
4
a
)
y^2 = a(x - 4a)
y
2
=
a
(
x
−
4
a
)
c.
y
2
=
4
a
(
x
−
4
a
)
y^2 = 4a(x - 4a)
y
2
=
4
a
(
x
−
4
a
)
d.
y
2
+
3
a
x
+
4
a
2
=
0
y^2 + 3ax + 4a^2 = 0
y
2
+
3
a
x
+
4
a
2
=
0
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