Physics

Physics

Problem

A straight rod of length LL extends from x=ax = a to x=L+ax = L + a. The gravitational force it exerts on point mass ' mm ' at x=0x = 0 , if the mass per unit length of the rod is A+Bx2A + Bx^2 , is given by: a. Gm[A(1a+L−1a)−BL]Gm \left[ A \left( \frac{1}{a+L} - \frac{1}{a} \right) - BL \right] b. Gm[A(1a−1a+L)−BL]Gm \left[ A \left( \frac{1}{a} - \frac{1}{a+L} \right) - BL \right] c. Gm[A(1a+L−1a)+BL]Gm \left[ A \left( \frac{1}{a+L} - \frac{1}{a} \right) + BL \right] d. Gm[A(1a−1a+L)+BL]Gm \left[ A \left( \frac{1}{a} - \frac{1}{a+L} \right) + BL \right]

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